-3x+1+x^2+3=180

Solution for -3x+1+x^2+3=180 equation:

-3x+1+x^2+3=180

We move all terms to the left:

-3x+1+x^2+3-(180)=0

We add all the numbers together, and all the variables

x^2-3x-176=0

a = 1; b = -3; c = -176;
Δ = b2-4ac
Δ = -32-4·1·(-176)
Δ = 713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{713}}{2*1}=\frac{3-\sqrt{713}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{713}}{2*1}=\frac{3+\sqrt{713}}{2}
$